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楼主我想问一下,我的6050示例程序是这样的:
unsigned char Re_buf[11],counter=0;
unsigned char sign=0;
float a[3],w[3],angle[3],T;
void setup() {
// initialize serial:
Serial.begin(115200);
}
void loop() {
if(sign)
{
sign=0;
if(Re_buf[0]==0x55) //检查帧头
{
switch(Re_buf [1])
{
case 0x51:
a[0] = (short(Re_buf [3]<<8| Re_buf [2]))/32768.0*16;
a[1] = (short(Re_buf [5]<<8| Re_buf [4]))/32768.0*16;
a[2] = (short(Re_buf [7]<<8| Re_buf [6]))/32768.0*16;
T = (short(Re_buf [9]<<8| Re_buf [8]))/340.0+36.25;
break;
case 0x52:
w[0] = (short(Re_buf [3]<<8| Re_buf [2]))/32768.0*2000;
w[1] = (short(Re_buf [5]<<8| Re_buf [4]))/32768.0*2000;
w[2] = (short(Re_buf [7]<<8| Re_buf [6]))/32768.0*2000;
T = (short(Re_buf [9]<<8| Re_buf [8]))/340.0+36.25;
break;
case 0x53:
angle[0] = (short(Re_buf [3]<<8| Re_buf [2]))/32768.0*180;
angle[1] = (short(Re_buf [5]<<8| Re_buf [4]))/32768.0*180;
angle[2] = (short(Re_buf [7]<<8| Re_buf [6]))/32768.0*180;
T = (short(Re_buf [9]<<8| Re_buf [8]))/340.0+36.25;
break;
}
}
}
}
void serialEvent() {
while (Serial.available()) {
//char inChar = (char)Serial.read(); Serial.print(inChar); //Output Original Data, use this code
Re_buf[counter]=(unsigned char)Serial.read();
if(counter==0&&Re_buf[0]!=0x55) return; //第0号数据不是帧头
counter++;
if(counter==11) //接收到11个数据
{
counter=0; //重新赋值,准备下一帧数据的接收
sign=1;
}
}
}
需要三次loop才能读出来1组9个数据,我需要怎样才能一次读取出来9个数据呢?我用的是串口传输。 |
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